Find the value of x in the given trapezium ABCD.
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Answered by
3
Answer:
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Step-by-step explanation:
first of all this is parallelogram not a trapezium.
x-22+x+42=180(the sum of adjacent angles of parallelogram is 180)
2x+20=180
2x=160
x=80
Answered by
7
Answer:
The answer to your question is 80
Step-by-step explanation:
Since ABCD is trapezium
AB||CD
So, Angle A + Angle D = 180° [alternate interior angles]
x-22+x+42 = 180
2x + 20 = 180
2x = 180 - 20
2x = 160
x=80
Hope it helped you
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