Math, asked by kaurg6087, 8 months ago

Find the value of x in the given trapezium ABCD.


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Answers

Answered by sufyanraza929
3

Answer:

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Step-by-step explanation:

first of all this is parallelogram not a trapezium.

x-22+x+42=180(the sum of adjacent angles of parallelogram is 180)

2x+20=180

2x=160

x=80

Answered by Anonymous
7

Answer:

The answer to your question is 80

Step-by-step explanation:

Since ABCD is trapezium

AB||CD

So, Angle A + Angle D = 180° [alternate interior angles]

x-22+x+42 = 180

2x + 20 = 180

2x = 180 - 20

2x = 160

x=80

Hope it helped you

If it helped you then plz mark this as brainliest!

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