Question

Find the value of x in the square PQRS​

Answer 1

SOR = 78°

=>TOQ = 78°(VOA)

OQT = 45°(angle bisector)

PTO = TOQ + OQT(theorem)

PTO = x= 78° + 45°

$x$ = 123°

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Answer 2

Answer:

angle RSQ=45 (bisector of angle PSR)

angel SQT=45 (adjacent angle)

angle TOQ=78. (vertically opposite)

angle OTQ=180-123=57 (sum of interior angle of triangle)

x=180-57 =123. (linear pair)