Question

Find the value of 'x' in x/5 = 39/15 ​

Answer 1

Answer :-

$Q) \: \sf \dfrac{x}{5} = \dfrac{39}{15}$

Transposing 5 from LHS to RHS, changing it's sign,

$\leadsto\sf x = \dfrac{39}{15} \times 5$

Reducing the numbers,

$\leadsto \sf x = \dfrac{13}{1} \times 1$

Now let's multiply the remaining numbers since we can't reduce them anymore.

$\leadsto \sf x = 13 \times 1$

Multiplying 13 with 1,

$\leadsto \underline{\boxed{\sf x = 13}}$

-------------------------------------------

V E R I F I C A T I O N :-

To check our answer, let's put 13 in the place of x and see whether LHS = RHS.

LHS

$\longmapsto\tt \dfrac{x}{5}$

Substituting the value of x,

$\longmapsto\tt \dfrac{13}{5}$

RHS

$\longmapsto\tt \dfrac{39}{15}$

Reducing the numbers,

$\longmapsto\tt \dfrac{13}{5}$

Since LHS = RHS,

Hence verified!