Find the value of x, of x=√6+√6+√6+.... infinity where x is a natural number.
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Answer: The answer is 3
I hope my explanation helps!
Step-by-step explanation:
Let : x= root(6+root(6 + root(6 + ………
Therefore,
x= root(6+x)
x^2=6+x
x^2-x-6=0
(x-3)(x+2)=0
So, x=3 or -2.
Since the question is to find a natural number keep 3 and remove -2
Answered by
1
HEY MATE HERE IS UR ANSWER
X=√6+√6+√6........infiniy
X=√(6+x)
Squaring both the sides , we get
x^2=6+x
x^2-x-6=0
x^2-3x+2x-6=0
x(x-3)+2(x-3)=0
(x+2)(x-3)=0
x=-2 or x=3
HOPE U UNDERSTOOD IT
PLZZZ CHOOSE IT AS BRAINLIEST
X=√6+√6+√6........infiniy
X=√(6+x)
Squaring both the sides , we get
x^2=6+x
x^2-x-6=0
x^2-3x+2x-6=0
x(x-3)+2(x-3)=0
(x+2)(x-3)=0
x=-2 or x=3
HOPE U UNDERSTOOD IT
PLZZZ CHOOSE IT AS BRAINLIEST
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