Question

Find the value of x power 2 divid x power 7

Answer 1

Step-by-step explanation:

x^2/x^7 = x^2-7=x^-5 = 1/x^5

Answer 2

Step-by-step explanation:

Let us first divide the given polynomial x

Let us first divide the given polynomial x 4 +x

Let us first divide the given polynomial x 4 +x 3 +8x

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x 2

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x 2 +1, therefore, the remainder must be equal to 0 that is:

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x 2 +1, therefore, the remainder must be equal to 0 that is:(a−1)x+(b−7)=0

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x 2 +1, therefore, the remainder must be equal to 0 that is:(a−1)x+(b−7)=0⇒(a−1)x+(b−7)=0⋅x+0

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x 2 +1, therefore, the remainder must be equal to 0 that is:(a−1)x+(b−7)=0⇒(a−1)x+(b−7)=0⋅x+0⇒(a−1)=0,(b−7)=0(Bycomparingcoefficients)

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x 2 +1, therefore, the remainder must be equal to 0 that is:(a−1)x+(b−7)=0⇒(a−1)x+(b−7)=0⋅x+0⇒(a−1)=0,(b−7)=0(Bycomparingcoefficients)⇒a=1,b=7

Let us first divide the given polynomial x 4 +x 3 +8x 2 +ax+b by (x 2 +1) as shown in the above image:From the division, we observe that the quotient is x 2 +x+7 and the remainder is (a−1)x+(b−7).Since it is given that x 4 +x 3 +8x 2 +ax+b is exactly divisible by x 2 +1, therefore, the remainder must be equal to 0 that is:(a−1)x+(b−7)=0⇒(a−1)x+(b−7)=0⋅x+0⇒(a−1)=0,(b−7)=0(Bycomparingcoefficients)⇒a=1,b=7Hence, a=1 and b=7.