Question

Find the value of x so that (2^-1 +4^-1 +6^-1 +8^-1)x= 1

Answer 1

Answer:

X = 0

Step-by-step explanation:

a^0=1

Answer 2

Answer:

The value of x is $\frac{24}{25}$

Step-by-step explanation:

• We have to get the sum of all the numbers that are inside the braket
  $\frac{1}{2} +\frac{1}{4} + \frac{1}{6} + \frac{1}{8}$
• The lcm of 2,4,6,8 is 24 hence the sum is
  $\frac{1}{2} +\frac{1}{4} + \frac{1}{6} + \frac{1}{8} \\\\\frac{12+6+4+3}{24} \\\frac{25}{24}$
• Hence the value of x becomes
  $\frac{25}{24} * x = 1\\ x = \frac{1}{\frac{25}{24}}$
• Hence the value of x is $\frac{24}{25}$
  #SPJ3