Find the value of x so that 4-(3x+7) +x/5 divide by 5x+x/2+3(x-1) give 2
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[4(3x+7)+x/5]÷[5x+x/2+3(x-1)]=2
[12x+28+x/5] ÷[5x+x/2+3x-3]=2
[60x+140+x/5]÷[10x+x+6x-6/2]=2
[61x+140/5]÷[17x-6/2]=2
(61x+140)2÷(17x-6)5=2
(122x+280)÷(85x-30)=2
122x+280=2(85x-30)
122x+280=170x-60
280-60=170x-122x
220=48x
x=220÷48
x=4.5
[12x+28+x/5] ÷[5x+x/2+3x-3]=2
[60x+140+x/5]÷[10x+x+6x-6/2]=2
[61x+140/5]÷[17x-6/2]=2
(61x+140)2÷(17x-6)5=2
(122x+280)÷(85x-30)=2
122x+280=2(85x-30)
122x+280=170x-60
280-60=170x-122x
220=48x
x=220÷48
x=4.5
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