Question

find the value of x square + 1 by x square if x minus one by x is equal to root 3​

Answer 1

Answer:

8

Step-by-step explanation:

it is ismilar to the identify :

( a-b)^2 = a^2 + b^2 - 2ab

so here as it is x - 1/x

then the formula will be :

(x - 1/x )^2 = x^2 + 1/x^2  - 2 ( x × 1 / x = 1 )

as x - 1/x = @3                          ( im using this as root @ )

@3 x @3 = x^2 + 1/x^2 - 2

3+5 = x^2 + 1/x^2

8 = x^2 + 1/x^2

please mark it as brainliest :) if you understood  this method