Question

Find the value of x square + 1 by x square, if x minus one upon X is equals to root 3

Answer 1

Answer:

Value of $x^2+\frac{1}{x^2}\:\:is\:\:5$

Step-by-step explanation:

Given:

$x-\frac{1}{x}=\sqrt{3}$

To find: value of $x^2+\frac{1}{x^2}$

We use the identity,

( a - b )² = a² + b² - 2ab

take, a = x  and b = 1/x

we have,

$(x-\frac{1}{x})^2=(x)^2+(\frac{1}{x})^2-2(x)(\frac{1}{x})$

$(\sqrt{3})^2=x^2+\frac{1}{x^2}-2$

$x^2+\frac{1}{x^2}=3+2$

$x^2+\frac{1}{x^2}=5$

Therefore, Value of $x^2+\frac{1}{x^2}\:\:is\:\:5$

Answer 2

Step-by-step explanation:

hope it helpful