Question

how to find zeroes of polynomial 4u^2+8u.

Answer 1

Gd mrng..
Hope it helps u mate!!!!!

Answer 2

Here is yr answer
${4u {}^{2} } \: + 8u = 4u(u + 2) = 0 \\ u = - 2 \: \: \: \: \: \: \: u = 0 \div 4 = 0$
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