find the value of x square + 4 y square + 9 z square + 4 x y + 12 y z + 6 x z , when x = 8,y=7,z=6
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Answer:
900 is the answer
Step-by-step explanation:
the equation:- x^2+4y^2+9z^2+4xy+12yz+6xz can be simplified as:-
(x+2y+3z)^2
using formula:-( a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca
now put the values of x,y,z in simplified equation
(x+2y+3z)^2
(8+2×7+3×6)^2
(8+14+18)^2
(30)^2
900
hope i helped u
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