Math, asked by anjud0139, 7 months ago

find the value of x square + 4 y square + 9 z square + 4 x y + 12 y z + 6 x z , when x = 8,y=7,z=6​

Answers

Answered by simmi6791
2

Answer:

900 is the answer

Step-by-step explanation:

the equation:- x^2+4y^2+9z^2+4xy+12yz+6xz can be simplified as:-

(x+2y+3z)^2

using formula:-( a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca

now put the values of x,y,z in simplified equation

(x+2y+3z)^2

(8+2×7+3×6)^2

(8+14+18)^2

(30)^2

900

hope i helped u

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