Question

Find the value of x such that :-
1/16×(1/2)^2 = (1/2)^3(x-2)​

Answer 1

Answer:

$\frac{1}{16} \times ({ \frac{1}{2} })^{2} = { \frac{1}{2} }^{3} (x - 2) \\ \\ \frac{1}{16} \times \frac{1}{4} = \frac{1}{8} (x - 2) \\ \\ \frac{1}{64} = \frac{1}{8} (x - 2) \\ \\ \frac{1}{64} \times \frac{8}{1} = (x - 2) \\ \frac{8}{64} = x - 2 \\ \\ \frac{1}{8} = x - 2 \\ x = \frac{1}{8} + 2 \\ \\ x = \frac{1 + 16}{8} \\ \\ x = \frac{17}{8}$

I HOPE THIS HELP U

Answer 2

Answer:

1/16×(1/2)^2=(1/2)^3 (x-2)

(1/4)^2×(1/2)^2=(1/2)^3 (x-2)

(1/8)^3=(1/8) (x-2)

1/64×8/1=x-2

1/8=x-2

1/8+2=x

1+16/8=x

17/8=x

2.12=x

or

x=2.12