Question

Find the value of x, such that (3/5 )^-3 (⅗ )^-12= ( ⅗ )^-5x

Answer 1

Answer:

(3/5)³ × (3/5)^-6 = (3/5)^2x-1

(3/5)^3+(-6) = (3/5)^2x-1

(a^m×aⁿ = a^m+n)

Bases are equal. Exponents must be equal.

3+(-6) = 2x-1

3-6 = 2x-1

-3 = 2x-1

2x = -3+1

2x = -2

x = -2/2

x = -1

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Step-by-step explanation:

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Answer 2

Answer

-3

Step-by-step explanation:

(3/5)^-3×(3/5)^-12=(3/5)^-5x

Let's take only powers

-3+-12=-5x

-15=-5x

-15/-5=x

-3=x