Find the value of x, such that (3/5 )^-3 (⅗ )^-12= ( ⅗ )^-5x
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Answered by
3
Answer:
(3/5)³ × (3/5)^-6 = (3/5)^2x-1
(3/5)^3+(-6) = (3/5)^2x-1
(a^m×aⁿ = a^m+n)
Bases are equal. Exponents must be equal.
3+(-6) = 2x-1
3-6 = 2x-1
-3 = 2x-1
2x = -3+1
2x = -2
x = -2/2
x = -1
Hope it helps
Step-by-step explanation:
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Answered by
0
Answer
-3
Step-by-step explanation:
(3/5)^-3×(3/5)^-12=(3/5)^-5x
Let's take only powers
-3+-12=-5x
-15=-5x
-15/-5=x
-3=x
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