find the value of x such that AB=BC ,where A,B and C are the points (6,-1)(1,3)and( x,8) respectively
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value of x is 3.
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We need to find the value of x such that AB = BC. We know that the distance between the points (x1, y1) and (x2, y2) is ⇒ AB = BC ⇒ AB2 = BC2 ⇒ (6 - 1)2 + (1 - 3)2 = (1 - x)2 + (3 - 8)2 ⇒ (5)2 + (- 2)2 = (1 - x)2 + (- 5)2 ⇒ 25 + 4 = 1 - 2x + x2 + 25 ⇒ x2 - 2x - 3 = 0 ⇒ x2 - 3x + x - 3 = 0 ⇒ x(x - 3) + 1(x - 3) = 0 ⇒ (x + 1)(x - 3) = 0 ⇒ x + 1 = 0 (or) x - 3 = 0 ⇒ x = - 1 (or) x = 3 ∴ The values of x are - 1 or 3
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