Solve the following pair of linear equations using substitution method 2. 2 + 3 + 5 = 0 ; 5 − 3 + 9 = 0
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0.2x+0.3y=1.3 (1)
0.4x+0.5y=1.3 .(
2)
Derive the value of y from equation (1)
y=0.31.3−0.2x (3)
Substitute value of y in equation(3)
0.4x+0.5(0.31.3−0.2x)=2.30.12x+0.5(1.3−0.2x)=0.690.12x+0.65−0.1x=0.690.02x=0.64x=32
Substitute value of x in equation (3)
y=0.31.3−0.2(32)=0.31.3−6.4=−17
So, x=32 and y=-17
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