Question

Find the value of x

$(-7/9)^{-5}$ × $(-7/9)^{-17}$ = $(-7/9)^{2+3x}$

Answer 1

ANSWER...... ..........

Answer 2

Answer:

We know:

${a}^{m} \times {a}^{n} \: = {a}^{m + n}$

Given

${ \frac{ - 7}{9} }^{ - 5} \times \frac{ - 7}{9}^{ - 17} = \frac{ - 7}{9}^{2 + 3x} \\ \frac{ - 7}{9}^{ - 22} = \frac{ - 7}{9}^{2 + 3x} \\ when \: bases \: are \: same \:powers \: are \: equal \\ - 22 = 2 + 3x \\ - 24 = 3x \\ x = - 8$