Find the value of x
when three points
(1,8) (5, 12) and (x, 28) lies on
straight line using slope
Plzzz answer this for assignment
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Given:
The three points (1,8) (5, 12) and (x, 28) lies on straight line
To find:
Find the value of x
Solution:
From given, we have,
The condition is,
If the points lie on a straight line then the area of the triangle formed by these points will be zero.
Hence by area of triangle formula, we get,
0 = 1/2 | x₁ (y₁ - y₂) + x₂ (y₂ - y₃) + x₃ ( y₃ - y₁) |
0 = 1 ( -4) + 5 ( -16) + x (20)
0 = | -4-80+20x |
84 = 20x
x = 4.2
Therefore, the value of x is 4.2
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