find the value of x which the distance between the points A(2,-3) and B(x,5) is 10 units
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sq of 10=sq of(x-2)+sq of(5-×-3)
100=sq of(x-2)+sq of(5+3)
100=sq of(x-2)+64
sq of(x-2)=100-64=36
x-2=√36=6
x=6+2
x=8unit
100=sq of(x-2)+sq of(5+3)
100=sq of(x-2)+64
sq of(x-2)=100-64=36
x-2=√36=6
x=6+2
x=8unit
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