Question

Find the value of x

x² - 2x - 8 ​

Answer 1

$\huge\bigstar\blue{Answer}$

x² - 2x - 8

= = > x² - 4x + 2x - 8

= = > x ( x - 4 ) + 2 ( x - 4 )

= = > ( x + 2 ) ( x - 4 )

= = > x = -2,4

__________________________

Answer 2

$\sf\implies x^2 - 2x - 8=0$

$\sf\implies x^2 - 4x + 2x - 8=0$

$\sf\implies x ( x - 4 ) + 2 ( x - 4 )=0$

$\sf\implies ( x + 2 ) ( x - 4 )=0$

$\sf\implies (x+2)=0,(x-4)=0$

$\sf\implies\fbox {x = -2,4}$