Find the value of x y 3 in the adjoining figure
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Answered by
1
Answer:
ANSWER
In△BCE
⟹∠BEC+∠BCE+∠CBE=180
∘
⟹90
∘
+30
∘
+∠CBE=180
∘
⟹∠CBE=60
∘
y=60
∘
In△APC:
⟹50
∘
+30
∘
+∠APC=180
∘
⟹∠APC=100
∘
∴x=180−∠APC
(∵sumofanglesonastraightline=180
∘
)
⟹x=180
∘
−100
∘
=80
∘
In△BOP:
z=x+y(exteriorangleofatriangle=sumoftwooppositeinteriorangles)
⟹z=80+60=140
∘
∴x=80
∘
,y=60
∘
,z=140
∘
Answered by
0
Answer:
which figure??
ur question is not complete
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