find the value of x y and z in the following figures .
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Answered by
3
by linear equation,
84°+ Z =180°
Z=180°-84°
Z=96°
We know sum of angle of triangle is 180°,
20°+y+96°=180
y=64°
again,
58°+84°+x=180°
142°+x=180°
x=180°-142°
x=38°..
hence,
x=38°
y=64°
z=96°.....
84°+ Z =180°
Z=180°-84°
Z=96°
We know sum of angle of triangle is 180°,
20°+y+96°=180
y=64°
again,
58°+84°+x=180°
142°+x=180°
x=180°-142°
x=38°..
hence,
x=38°
y=64°
z=96°.....
Answered by
2
ang z=180-84 (linear pair)
ang z=96
ang y+20+96=180(ang sum property of triangle)
ang y+116=180
ang y=180-116
ang y=64
58+84+x=180(ang sum property of triangle)
angX=180-142
ang x=38
I hope it helps you
if you like it pls select this answer as brainlist
ang z=96
ang y+20+96=180(ang sum property of triangle)
ang y+116=180
ang y=180-116
ang y=64
58+84+x=180(ang sum property of triangle)
angX=180-142
ang x=38
I hope it helps you
if you like it pls select this answer as brainlist
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