Find the value of (x, y) if centroid of triangle with vertices (x, 0),(0,y)and(6,3)is(3,4)...solution
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Answered by
2
Answer:
Centroid → (3,4).
Vertices → (11,0), (0,4), (6,3)
(x,y) →?
centroid (x₁ + x₂ + x3 y, ty.. 3
of triangle = x² +0+6 0+y+3 3
3
= x+6
+3
3
५+३
x+6=3
3 x = 9-6
x=3
(x^. y) = (3,9),
3 y+3=4 3
y=92=6 = 9 y
Answered by
0
Answer:
y=92=6 = 9 y
Step-by-step explanation:
Centroid → (3,4).
Vertices → (11,0), (0,4), (6,3)
(x,y) →?
centroid (x₁ + x₂ + x3 y, ty.. 3
of triangle = x² +0+6 0+y+3 3
3
= x+6
+3
3
५+३
x+6=3
3 x = 9-6
x=3
(x^. y) = (3,9),
3 y+3=4 3
y=92=6 = 9 y
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