Question

find the value of (x+y)(x+y+z)​

Answer 1

Answer:

x+y =z

$x {?}^{2}$

Answer 2

Answer:

hello mate!

Step-by-step explanation:

The value of (x+y)(x+y+z)

using distributive law,

(Splitting of a product as sum of 2 or More products/ Difference of 2 or more products)

(Here, it's Multiplication over addition, we also have another methodology called as,

Multiplication over subtraction)

1)(A+b)(a+b+c)= a(a+b+c)+b(a+b+c)

2)a+b+c(a+b)= a(a+b)+b(a+b)+c(a+b)

1) x+y(x+y+z)= x(x+y+z)+y(x+y+z)

x²+xy+xz+yx+y²+yz.

(Like terms) x²+2xy+Xz+Yz+y².

2)X+Y+Z(X+Y)=X(X+Y)+Y(X+Y)+Z(X+Y)

x²+xy+yx+y²+Zx+Zy

(Like terms)=X² +2Yx+Zx+Zy+Y².

hence,

The answer is x²+2xy+Zx+Zy+Y².

and,

Arranging them in any order, Is correct only when it is In the operation:- addition,

as addition is commutative

Thank you mate!

Have a great day ahead!