Find the value of (x+y+z)² If x² + y²+z²=20 and xy + yz +zx = 30
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Answer:
x+y+z = 6 …(1)
xy+yz+zx = 11 …(2)
What is x^2+y^2+z^2?
(x+y+z)^2 = x^2+y^2+z^2 + 2xy + 2yz + 2 xz = (x^2+y^2+z^2) +2(xy+yz+zx)
x^2+y^2+z^2 = (x+y+z)^2 - 2(xy+yz+zx) = 6^2 - 2*11 = 36 - 22 = 14. Answer
Step-by-step explanation:
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