Question

Find the value of x°​

Answer 1

Solution:

Given:

$\angle ACB = 90°$

$\angle BAC = 40°$

$\angle AEF = 100°$

Concept:

• Here the ∆ ABC is a right - angled triangle , so by the given two angles we can find the third angle.
• From the figure it is concluded that the figure EBD is a triangle .so by the two angles we can find the value of x .

We Know:

Sum of angles of a triangle is 180°.

Answer:[For ∆ABC]

➜ $\angle ACB = 90°$

➜ $\angle BAC = 40°$

• Let the third angle be y.

[sum of triangle = 180°]

so , $\angle ACB + \angle BAC + \angle ABC = 180°$

$90° + 40° + y = 180°$

$130° + y = 180°$

$y = 180° - 130°$

$y = 50°$

Answer:[For ∆ EBD]

➜ $\angle AEF = 100°$

➜ $\angle EBD = 50°$

• Given the third angle is x.

[sum of triangle = 180°]

so , $\angle AEF + \angle EBD + \angle EDB = 180°$

$100° + 50° + x = 180°$

$150° + x = 180°$

$x = 180° - 150°$

$x = 30°$

Hence ,the value of x is 30°.