Question

Find the value of x3 + 3x²y + 3xy2 + y3 if x = 2 and y= 3. please help me ​

Answer 1

Answer:

Ok here is your answer

2³+ 3(2²(3))+ 3(2)(3)²+ 3³=125

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Answer 2

$x^{3}$ + 3x²y + 3x$y^{2}$ + $y^{3}$

if x = 2 and y= 3

$2^{3}$ + (3 × $2^{2}$ × 3) + (3 × 2 × $3^{2}$)+ $3^{3}$

= 8 + (3 × 4 × 3) + (3 × 2 × 9) + 27

= 8 + (36) + (54) + 27

= 125