find the value of x³+y³-12xy+65if x+y=4
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we know
(x+y)^3=x^3+y^3-3xy(x+y)
here given x+y=4
(4)^3=x^3+y^3-3xy(4)+65
64=x^3+y^3-12xy(4)+65
hey here value of x y is not given something is wrong about it
noorul9:
what
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Answer: I got 3(43-8xy)
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