Question

find the value of x³+y³+z³-3xyz ​

Answer 1

Answer:

a - 108

Step-by-step explanation:

x³+y³+z³-3xyz = (x+y+z)(x²+y²+z²-xy-yz-xz)

(x+y+z) = 9

xy+yz+xz = 23

=> x³+y³+z³-3xyz = 9(x²+y²+z²-23)

(x+y+z)² = x²+y²+z²+2(xy+yz+xz)

9² = x²+y²+z²+2x23

=> 81 = x²+y²+z²+46

=> x²+y²+z² = 81 - 46 = 35

We have,

x³+y³+z³-3xyz = 9(x²+y²+z²-23)

=> x³+y³+z³-3xyz = 9(35-23) = 9x12 = 108

Answer 2

Answer:

the answer will be -108