find the value of (x⁴+y⁴) and (x²-x²)² when x²+y²= 5 and xy= 5
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Hello Friend,
Here we are given:
x² + y² = 5
xy = 5
Now,
• x⁴ + y⁴
= (x²)² + (y²)² + 2x²y² - 2x²y²
= (x² + y²)² - 2(xy)²
= 5² - 2×5²
= 25 - 50
= -25
• (x² - y²)²
= x⁴ + y⁴ - 2x²y²
= x⁴ + y⁴ + 2x²y² - 4x²y²
= (x² + y²)² - 4x²y²
= 5² - 4×5²
= 25 - 100
= -75
Hope it helps.
Purva
@Purvaparmar1405
Brainly.in
Here we are given:
x² + y² = 5
xy = 5
Now,
• x⁴ + y⁴
= (x²)² + (y²)² + 2x²y² - 2x²y²
= (x² + y²)² - 2(xy)²
= 5² - 2×5²
= 25 - 50
= -25
• (x² - y²)²
= x⁴ + y⁴ - 2x²y²
= x⁴ + y⁴ + 2x²y² - 4x²y²
= (x² + y²)² - 4x²y²
= 5² - 4×5²
= 25 - 100
= -75
Hope it helps.
Purva
@Purvaparmar1405
Brainly.in
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