find the value of y..............
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Hey there! Hello.
See the solution in the attachment.
Hope this helps......
See the solution in the attachment.
Hope this helps......
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Hi
[ 4^2+y × 8^2y - 3 ]/32^3y = 2^-26
[(2)^2(2+y)×(2)^3(2y-3)]/2^5×3y=2^-26
[2^4+2y × 2^6y-9]= 2^-26 × 2^15y
[ 2^4+2y+6y-9 ] = 2^-26+15y
[ a^m × a^n = a^m+n ]
2^8y - 5 = 2^ -26 + 15y
8y - 5 = -26 + 15y
[ If a^m = a^n then m = n ]
26 - 5 = 15y - 8y
21 = 7y
21/7 = y
3 = y
Therefore ,
y = 3
I hope this helps you.
: )
[ 4^2+y × 8^2y - 3 ]/32^3y = 2^-26
[(2)^2(2+y)×(2)^3(2y-3)]/2^5×3y=2^-26
[2^4+2y × 2^6y-9]= 2^-26 × 2^15y
[ 2^4+2y+6y-9 ] = 2^-26+15y
[ a^m × a^n = a^m+n ]
2^8y - 5 = 2^ -26 + 15y
8y - 5 = -26 + 15y
[ If a^m = a^n then m = n ]
26 - 5 = 15y - 8y
21 = 7y
21/7 = y
3 = y
Therefore ,
y = 3
I hope this helps you.
: )
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