Question

find the value of y for which the distance between the points P(2,-3) and Q (10,y) is 10 units

Answer 1

hello.
the formula to calculate the distance between two points (a,b) and (c,d) is given by
dist d = √(a-c)² + (b-d)²

applying it for this ques we have d=10 units
10 = √(2 - 10)² + (-3-y)²
squaring both sides
100 = (-8)² + (9 + y² + 6y)
100 = 64 +9 + y² + 6y
y² + 6y - 27 = 0
y² + 9y - 3y - 27 = 0
y(y + 9) -3(y + 9) = 0
(y-3)(y+9) = 0
y=3 or y=-9

both values of y are possible unless no other condition is specified in the question.


hope it helps

Answer 2

Answer:Hey, friends here is the answer you are looking.

understand the question and do it.