Question

Find the value of y for which the distance between the points P (2, -3) and Q (10, y) is 10 units4

Answer 1

Step-by-step explanation:

Given, P (2, -3) and Q (10, y)

10 = √(10-2)² + (y-3)²

y = 9, -3

Answer 2

Answer:

y = -9 or y = 3

Step-by-step explanation:

Let P(2, -3) be (x1, y1) &

Q(10, y) be (x2, y2)

Now,

Using the Distance formula:

d(PQ) = √(x2 - x1)^2 + (y2 - y1)^2

= √(10 - 2)^2 + (y + 3)^2

= √ 64 + y^2 + 6y + 9

= √ y^2 + 6y + 73

i.e

10 = √ y^2 + 6y + 73

Squaring both the sides:

100 = y^2 + 6y + 73

y^2 + 6y - 27 = 0

y^2 + 9y - 3y - 27 = 0

y(y+9) -3(y+9) = 0

(y+9) (y-3) = 0

Hence here,

y = -9 or y = 3