Question

in figure 11,AD and CE are respectively perpendicular to sides BC and AB of ABC . IF ANGLE ECD = 45° find angle BAD.​

Answer 1

Answer:

45°

Step-by-step explanation:

Angle BEC is 90°

So, in triangle BEC,

Angle EBC + Angle BEC + Angle BCE = 180

Angle EBC + 90 + 45 = 180

Angle EBC = 180 - 135

Angle EBC = 45

Now, Angle ADB is 90°

So, in triangle ADB,

Angle ADB + Angle ABD + Angle BAD = 180

Angle BAD + 90 + 45 = 180

Angle BAD = 180 - 135

Angle BAD = 45

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Answer 2

Answer:

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