Question

Find the value of y, if (2/7)^y = 1​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

To Find:

Value of the exponent $\tt{y}$ in the above equation.

Equation:

$\boxed{\tt{{(\frac {2}{7})}^{y}=1}}$

Rule to be used:

$\boxed{\tt{{(x)}^{0}=1}}$

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$\tt{{(\frac {2}{7})}^{y}=1}$

(Equation given in the question)

$\tt{\implies {(\frac {2}{7})}^{y}= {(\frac {2}{7})}^{0}}$

(As we know, x^0 = 1, hence to make the bases same, we have changed it into (2/7)^0)

As bases are same,

$\boxed{\large\tt\green{\therefore y = 0}}$

$\boxed{\text{(Answer)}}$

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Verification:

(Value of y = 0)

Left Hand Side:-

$\tt{{(\frac {2}{7})}^{y}}$

(As per LHS)

$\tt{={(\frac {2}{7})}^{0}}$

(Placed Value of y)

$\tt{=1}$

(Value of Left Hand Side)

Right Hand Side:-

$\tt{1}$

(Value of Right Hand Side)

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$\boxed{\large\tt{\therefore LHS=RHS}}$