Question

Find the value of y if distance between p( 2 , -3 ) & q( 10 , y ) is 10 unitsr

Answer 1

Answer:

Step-by-step explanation:

distance=√(x₂-x₁)²+(y₂-y₁)²

10=√(10-2)²+(y+3)²

10=√64+(y+3)²

squaring on both sides

100=64+(y+3)²

(y+3)²=36

y+3=±6

y=9 or y=-3