Question

Find the value of y in 13y^2 - 248y + 496

Answer 1

if it's equal to 0

13y²-248y+496 = 0

y = -b±√(b²-4ac)/2a

put values a = 13 ,b = -248, C = 496

y = [248 ± 24√(62)]/26

= [124±12√62)]/13