Find the value of y in 13y^2 - 248y + 496
Answers
Answered by
1
if it's equal to 0
13y²-248y+496 = 0
y = -b±√(b²-4ac)/2a
put values a = 13 ,b = -248, C = 496
y = [248 ± 24√(62)]/26
= [124±12√62)]/13
Similar questions