find the value of Y so that EFGH is an isosceles trapezium
Fig.11.32
Attachments:
Answers
Answered by
7
Answer:
Y = 7
Step-by-step explanation:
2y^2 - 25 = y^2 + 24
y^2 = 49
√y^2 = √49
y = 7
Answered by
6
Answer:
y=7
Step-by-step explanation:
Since EFGH is an isoosceles trapezium and HG║EF, HE=GF, an ∠d HEF=∠GFE.
∴ 2y²-25=y²+24
y²=49, y=±7, -7 is neglected as length here vcant be of negative value.
⇒y=7.
Similar questions