Question

find the value of Y so that EFGH is an isosceles trapezium
Fig.11.32​

Answer 1

Answer:

Y = 7

Step-by-step explanation:

2y^2 - 25 = y^2 + 24

y^2 = 49

√y^2 = √49

y = 7

Answer 2

Answer:

y=7

Step-by-step explanation:

Since EFGH is an isoosceles trapezium and HG║EF, HE=GF, an ∠d HEF=∠GFE.

∴ 2y²-25=y²+24

y²=49, y=±7, -7 is neglected as length here vcant be of negative value.

⇒y=7.