Question

find the value of y such that the number 7y 3y 2is divisible by 11 answer in step by step​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

Given that, 2y5 is divisible by 11.

To find out: The value of y.

From the test of divisibility by 11, we know that, a number is divisible by 11, if the difference between the sum of digits at odd places and the sum of digits at even places is either 0 or a multiple of 11.

For 2y5, sum of digits at odd places =2+5=7

and sum of digits at even places =y.

Hence, 7−y or y−7 must be either 0 or some multiple of 11.

∴ 7−y=0⇒y=7

or 7−y=11⇒y=−4

or 7−y=22⇒y=−15

and so on.

or

y−7=0⇒y=7

or y−7=11⇒y=18

or y−7=22⇒y=29

and so on.

But, we observe that when the difference is 0, we get y=7

and if it is any multiple of 11, the value is either negative or more than one digit, which are both not possible.

Hence, the value of the difference must be 0.

∴ y=7

Hence, the value of y for which 2y5 is divisible by 11, is 7.

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