Question

Find the value of 'y' which satisfies the equation 1 + y^2/13 = √(27/169 +1)​

Answer 1

Step-by-step explanation:

$\frac{1 + {y}^{2} }{13} = \sqrt{( \frac{27}{169} ) + 1} \\ \frac{1 + {y}^{2} }{13} = \sqrt{ \frac{196}{169} } = \frac{14}{13} \\ 1 + {y}^{2} = 14 \\ {y}^{2} = 13 \\ y = \sqrt{13}$

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