Find the value of102×97 by using approximate value identity
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Answer:
using the identity:
(x+a)×(x+b)=x^2+(a+b)x+a×b
Here,
let x=100, a=2, b=3
so applying the identity,
(100+2)×(100-3)
=(100)^2 +{2+(-3)}×100 +2×(-3)
=10000+{2-3}×100-6
=10000-100-6
=9900-6
=9894.
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