find the value ofp(x)=2x^2-3x+1 when x=2
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Hi Ishika ,
Given x=2
GIven p(x) = 2x^2 - 3x +1
solution
put x = 2 in given equation
so
p(2) = 2(2)^2 - 3*2 + 1
= 2(4) - 6 +1
= 8-6+1
= 2-5
= 3
so p(x) = 3 when x=2
Hope it helped.
Let me know if any doubts.
Cheers !!!
Given x=2
GIven p(x) = 2x^2 - 3x +1
solution
put x = 2 in given equation
so
p(2) = 2(2)^2 - 3*2 + 1
= 2(4) - 6 +1
= 8-6+1
= 2-5
= 3
so p(x) = 3 when x=2
Hope it helped.
Let me know if any doubts.
Cheers !!!
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