Question

find the value ofx³+y²,of x+y=-14 and xy=84​

Answer 1

Answer:

-13x^2 -56x + 196

Step-by-step explanation:

Given x+y=-14

y= -x-14

xy=84

x(-x-14)=84

-x^2 -14x = 84

x^2+14x+84 =0

x^3 = -14x^2 -84x

y^2 = (x+14)^2

=x^2 + 28x + 196

x^3 + y^2 = -13x^2 - 56x + 196

Answer 2

Step-by-step explanation:

Have Given :-

$x+y=-14 \: \: and \: \: xy=84$

To find :-

${x}^{2} + {y}^{2} = ?$

Formula :-

$(x + y)^{2} = {x}^{2} + {y}^{2} + 2xy$

$( - 14)^{2} = {x}^{2} + {y}^{2} + 2(84)$

$196 = {x}^{2} + {y}^{2} + 168$

$196 - 168 = {x}^{2} + {y}^{2}$

$28 = {x}^{2} + {y}^{2}$

$or \: \: \: {x}^{2} + {y}^{2} = 28$

I hope it is helpful