Question

Find the value ot k if (1,-1) is the solution of equation (k+2)x-(3k-2)y-3=0

Answer 1

Answer:

put x = 1 & y = -1

we get

(k+2) 1 × ( 3 k -2) -1-3 =0

(k+2 ) × (-12k +8) =0

so k+2 =0. or. ,-12k +8. =0

k= -2. or. k= 2/3