Question

find the value p for which the point (p+1,2p-2), (p-1,p) and (p-3,2p-6) are colliner

Answer 1

Answer:

4

Step-by-step explanation:

{p - (2p-2)} / {(p-1) - (p+1)}  =  {(2p-6) - p } / {(p-3)-(p-1)}

(2-p)/(-2) =  (p-6)/(-2)

2-p = p-6

2p = 8

p =4