Question

find the value. p(x)=x^3-3x^2-2x+6 at x=√2​

Answer 1

p(x) = x³ - 3x² - 2x + 6

p(√2) = ?

==> (√2)³ - 3(√2)² - 2(√2) + 6

==> 2√2 - 3×2 - 2√2 + 6

==> 2√2 - 6 - 2√2 + 6

==> 2√2 - 2√2 + 6 - 6

==> 0