Question

Find the value(s) of k for which the equation x²+5kx+16=0 has real and equal roots​

Answer 1

Answer:

p(k)=x2 + 5kx +16 =0

step 1 . look which no. is not with any variable

step 2. in this equation the no. is 16

step 3. and then find the factors of 16

step 4 . the factors are 1 , 2 , 4,8,16

step 5 . take any no . from this i am taking 2

step 6. then put 2 repace the p and then put it

p(2 ) = 2(2) +5k2+16= 0

p(2)= 4 + 10k + 16 = 0

p(2) = 4+16=10k

p(2)= 20=10k

p(2) =20\10=k

p(2)=2 = k

so the ans is 2