Question

find the value (s) of K for which
the given quadratic equation has real
and equal root:
1) 9x²+ 8kr + 16 =0
2) kx (x - 2√5 )+ 10 = 0 ​

Answer 1

Answer:

Given equation is kx2-2√5kx+10=0. ∴ D=20k2-40k=20k(k-2). For real and equal roots, we must have D=0.

Answer 2

Step-by-step explanation:

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