find the value(s)of K for which the pair of linear equation kx + Y is =
K square and X + K Y = 1 have infinitely many solutions.
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Kxis equal tok kxplus isk square and x plus kyisequal to1 have infinitely many solution
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Kx + y = k²
X + KY = 1
As it have infinite solutions the lines are parellel
Hence, a1/a2 = b1/b2 = c1/c2
Therefore, k/1 = 1/k = k²/1
K = 1/k
K² = 1
K = root 1
Therefore k = +1 ,-1
X + KY = 1
As it have infinite solutions the lines are parellel
Hence, a1/a2 = b1/b2 = c1/c2
Therefore, k/1 = 1/k = k²/1
K = 1/k
K² = 1
K = root 1
Therefore k = +1 ,-1
CUTIESANU:
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