Question

Find the value(s) of k for which the pair of linear equations kx + y = k2 and x + ky = 1 have no solution

Answer 1

Answer:

According to question

Equations given

kx + y = k^2

and

x + ky = 1

Since the equations have infinitely many solutions

Thus

comparing the coefficients of x and y

k/1 = 1/k = 2k/1

thus

k = +1 or -1

k = +1/ root2 or -1/ root2

Answer 2

Answer:

k = -1

Step-by-step explanation:

for no solution the condition is a/A = b/B = c/C

$kx \: + y = k {}^{2}$

$x \: + ky = 1$

k/1 = 1/k ≠ k^2

k^2 = 1

k = ± 1. 1

also

k^3 ≠ 1

k ≠ 1. 2

from 1 and 2

k = -1