Find the value(s) of K for which the points (3k-1,k-2), (k,k-7) and (k-1,-k-2) are collinear.
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Formula is :1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2]=0
1/2[3k-1(k-7+k+2)+k(-k-2-k+2)+k-1(k-2-k+7)]=0
By using this solve k
1/2[3k-1(k-7+k+2)+k(-k-2-k+2)+k-1(k-2-k+7)]=0
By using this solve k
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